2x^2-7x-45=4

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Solution for 2x^2-7x-45=4 equation:


Simplifying
2x2 + -7x + -45 = 4

Reorder the terms:
-45 + -7x + 2x2 = 4

Solving
-45 + -7x + 2x2 = 4

Solving for variable 'x'.

Reorder the terms:
-45 + -4 + -7x + 2x2 = 4 + -4

Combine like terms: -45 + -4 = -49
-49 + -7x + 2x2 = 4 + -4

Combine like terms: 4 + -4 = 0
-49 + -7x + 2x2 = 0

Factor a trinomial.
(-7 + -2x)(7 + -1x) = 0

Subproblem 1

Set the factor '(-7 + -2x)' equal to zero and attempt to solve: Simplifying -7 + -2x = 0 Solving -7 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -2x = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -2x = 0 + 7 -2x = 0 + 7 Combine like terms: 0 + 7 = 7 -2x = 7 Divide each side by '-2'. x = -3.5 Simplifying x = -3.5

Subproblem 2

Set the factor '(7 + -1x)' equal to zero and attempt to solve: Simplifying 7 + -1x = 0 Solving 7 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1x = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1x = 0 + -7 -1x = 0 + -7 Combine like terms: 0 + -7 = -7 -1x = -7 Divide each side by '-1'. x = 7 Simplifying x = 7

Solution

x = {-3.5, 7}

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